134 lines
4.1 KiB
Lua
134 lines
4.1 KiB
Lua
--Summer winter time convertion
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--See: https://arduinodiy.wordpress.com/2015/10/13/the-arduino-and-daylight-saving-time/
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--
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--As October has 31 days, we know that the last Sunday will always fall from the 25th to the 31st
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--So our check at the end of daylight saving will be as follows:
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--if (dow == 7 && mo == 10 && d >= 25 && d <=31 && h == 3 && DST==1)
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--{
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--setclockto 2 am;
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--DST=0;
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--}
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--
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--To start summertime/daylightsaving time on the last Sunday in March is mutatis mutandis the same:
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--if (dow == 7 && mo == 3 && d >= 25 && d <=31 && h ==2 && DST==0)
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--{
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--setclockto 3 am;
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--DST=1;
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--}
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-- @fn isSummerTime(year, month, day, hour, minute, second,dow)
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-- The @param time is a struct containing the following entries:
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-- @var year Current year of day range (2016 - ...)
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-- @var month Current month of year range (1 - 12) e.g. 2 is Februrary
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-- @var day Current day in month range (1 - 31)
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-- @var hour Current hour of day range (0 - 23)
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-- @var minute Current minute in hour range (0 - 59)
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-- @var second Current second of minute range (0 - 59)
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-- @var dow Current day of week range (1 - 7) (1 is Monday, 7 is Sunday)
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-- @return <code>true</code> if we have currently summer time
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-- @return <code>false</code> if we have winter time
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function isSummerTime(time)
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-- we are in 100% in the summer time
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if (time.month > 3 and time.month < 10) then
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return true
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-- March is not 100% Summer time, only starting at the last sunday
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elseif ((time.month == 3 and time.day >= 25 and time.day <= 31 and time.hour > 2 and time.dow == 7) or
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-- Only handle days after the last sunday in this month
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((time.month == 3 and time.day >= 25 and time.day <= 31 and time.dow < 7 and ((7-time.dow + time.day) > 31))) ) then
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-- summer time
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return true
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-- October is not 100% Summer time, ending with the last sunday
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elseif ((time.month == 10 and time.day >= 25 and time.day <= 31 and (time.hour < 2 or (time.hour == 2 and time.minute== 0 and time.second == 0)) and time.dow == 7) or
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(time.month == 10 and time.day >= 25 and time.day <= 31 and time.dow < 7 and ((7-time.dow + time.day) <= 31)) or
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-- Handle all days up to the 25. of october
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(time.month == 10 and time.day < 25 )
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)then
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-- summer time
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return true
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end
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-- otherwise it must be winter time
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return false
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end
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----------------------------------------------------------
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-- Here comes some code to extract the year, month, day, hour, minute, second and day of week of a unix timestamp
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-- Source:
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-- http://www.jbox.dk/sanos/source/lib/time.c.html
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YEAR0=1900
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EPOCH_YR=1970
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--SECS_DAY=(24L * 60L * 60L)
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SECS_DAY=86400
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ytab = {}
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ytab[0] = {}
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ytab[1] = {}
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ytab[0][0] = 31
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ytab[0][1] = 28
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ytab[0][2] = 31
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ytab[0][3] = 30
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ytab[0][4] = 31
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ytab[0][5] = 30
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ytab[0][6] = 31
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ytab[0][7] = 31
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ytab[0][8] = 30
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ytab[0][9] = 31
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ytab[0][10] = 30
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ytab[0][11] = 31
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ytab[1][0] = 31
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ytab[1][1] = 29
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ytab[1][2] = 31
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ytab[1][3] = 30
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ytab[1][4] = 31
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ytab[1][5] = 30
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ytab[1][6] = 31
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ytab[1][7] = 31
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ytab[1][8] = 30
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ytab[1][9] = 31
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ytab[1][10] = 30
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ytab[1][11] = 31
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local leapyear = function(year)
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return ( not ((year) % 4 ~= 0) and (((year) % 100 ~= 0) or not ((year) % 400 ~= 0)))
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end
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local yearsize = function(year)
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if leapyear(year) then
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return 366
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else
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return 365
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end
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end
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function getUTCtime(unixtimestmp)
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local year = EPOCH_YR
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local dayclock = math.floor(unixtimestmp % SECS_DAY)
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dayno = math.floor(unixtimestmp / SECS_DAY)
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local sec = math.floor(dayclock % 60)
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local min = math.floor( (dayclock % 3600) / 60)
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local hour = math.floor(dayclock / 3600)
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local dow = math.floor( (dayno + 4) % 7) -- Day 0 was a thursday
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while (dayno >= yearsize(year))
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do
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dayno = dayno - yearsize(year);
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year=year + 1
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end
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--Day in whole year: local yday = dayno (Not needed)
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mon = 0
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while (dayno >= ytab[leapyear(year) and 1 or 0][mon])
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do
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dayno = dayno - ytab[leapyear(year) and 1 or 0][mon];
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mon = mon + 1
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end
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mday = dayno + 1
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return { year = year, month = (mon+1), day = mday, hour = hour, minute = min, second = sec, dow = dow }
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end
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