Wordclock/timecore.lua

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--Summer winter time convertion
--See: https://arduinodiy.wordpress.com/2015/10/13/the-arduino-and-daylight-saving-time/
--
--As October has 31 days, we know that the last Sunday will always fall from the 25th to the 31st
--So our check at the end of daylight saving will be as follows:
--if (dow == 7 && mo == 10 && d >= 25 && d <=31 && h == 3 && DST==1)
--{
--setclockto 2 am;
--DST=0;
--}
--
--To start summertime/daylightsaving time on the last Sunday in March is mutatis mutandis the same:
--if (dow == 7 && mo == 3 && d >= 25 && d <=31 && h ==2 && DST==0)
--{
--setclockto 3 am;
--DST=1;
--}
-- @fn isSummerTime(year, month, day, hour, minute, second,dow)
-- @param year Current year of day range (2016 - ...)
-- @param month Current month of year range (1 - 12) e.g. 2 is Februrary
-- @param day Current day in month range (1 - 31)
-- @param hour Current hour of day range (0 - 23)
-- @param minute Current minute in hour range (0 - 59)
-- @param second Current second of minute range (0 - 59)
-- @param dow Current day of week range (1 - 7) (1 is Monday, 7 is Sunday)
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-- @return <code>true</code> if we have currently summer time
-- @return <code>false</code> if we have winter time
function isSummerTime(year, month, day, hour, minute, second,dow)
-- we are in 100% in the summer time
if (month > 3 and month < 10) then
return true
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-- March is not 100% Summer time, only starting at the last sunday
elseif ((month == 3 and day >= 25 and day <= 31 and hour > 2 and dow == 7) or
-- Only handle days after the last sunday in this month
((month == 3 and day >= 25 and day <= 31 and dow < 7 and ((7-dow + day) > 31))) ) then
-- summer time
return true
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-- October is not 100% Summer time, ending with the last sunday
elseif ((month == 10 and day >= 25 and day <= 31 and (hour < 2 or (hour == 2 and minute== 0 and second == 0)) and dow == 7) or
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(month == 10 and day >= 25 and day <= 31 and dow < 7 and ((7-dow + day) <= 31)) or
-- Handle all days up to the 25. of october
(month == 10 and day < 25 )
)then
-- summer time
return true
end
-- otherwise it must be winter time
return false
end
-- Convert a given month in english abr. to number from 1 to 12.
-- On unknown arguments, zero is returned.
function convertMonth(str)
if (str=="Jan") then
return 1
elseif (str == "Feb") then
return 2
elseif (str == "Mar") then
return 3
elseif (str == "Apr") then
return 4
elseif (str == "May") then
return 5
elseif (str == "Jun") then
return 6
elseif (str == "Jul") then
return 7
elseif (str == "Aug") then
return 8
elseif (str == "Sep") then
return 9
elseif (str == "Oct") then
return 10
elseif (str == "Nov") then
return 11
elseif (str == "Dec") then
return 12
else
return 0
end
end
----------------------------------------------------------
-- Here comes some code to extract the year, month, day, hour, minute, second and day of week of a unix timestamp
-- Source:
-- http://www.jbox.dk/sanos/source/lib/time.c.html
YEAR0=1900
EPOCH_YR=1970
--SECS_DAY=(24L * 60L * 60L)
SECS_DAY=86400
ytab = {}
ytab[0] = {}
ytab[1] = {}
ytab[0][0] = 31
ytab[0][1] = 28
ytab[0][2] = 31
ytab[0][3] = 30
ytab[0][4] = 31
ytab[0][5] = 30
ytab[0][6] = 31
ytab[0][7] = 31
ytab[0][8] = 30
ytab[0][9] = 31
ytab[0][10] = 30
ytab[0][11] = 31
ytab[1][0] = 31
ytab[1][1] = 29
ytab[1][2] = 31
ytab[1][3] = 30
ytab[1][4] = 31
ytab[1][5] = 30
ytab[1][6] = 31
ytab[1][7] = 31
ytab[1][8] = 30
ytab[1][9] = 31
ytab[1][10] = 30
ytab[1][11] = 31
local leapyear = function(year)
return ( not ((year) % 4 ~= 0) and (((year) % 100 ~= 0) or not ((year) % 400 ~= 0)))
end
local yearsize = function(year)
if leapyear(year) then
return 366
else
return 365
end
end
function getUTCtime(unixtimestmp)
local year = EPOCH_YR
local dayclock = math.floor(unixtimestmp % SECS_DAY)
dayno = math.floor(unixtimestmp / SECS_DAY)
local sec = math.floor(dayclock % 60)
local min = math.floor( (dayclock % 3600) / 60)
local hour = math.floor(dayclock / 3600)
local dow = math.floor( (dayno + 4) % 7) -- Day 0 was a thursday
while (dayno >= yearsize(year))
do
dayno = dayno - yearsize(year);
year=year + 1
end
--Day in whole year: local yday = dayno (Not needed)
mon = 0
while (dayno >= ytab[leapyear(year) and 1 or 0][mon])
do
dayno = dayno - ytab[leapyear(year) and 1 or 0][mon];
mon = mon + 1
end
mday = dayno + 1
return { year = year, month = (mon+1), day = mday, hour = hour, minute = min, second = sec, dow = dow }
end